How do I count the number of capturing groups in java?

Capturing groups are numbered by counting their opening parentheses from left to right. To find out how many groups are present in the expression, call the groupCount() method on a matcher object. The groupCount() method returns an int showing the number of capturing groups present in the matcher's pattern.

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class CountingGroupDemo {
    public static void main(String[] args) {
        //
        // Define regex to find the word 'quick' or 'lazy' or 'dog'
        //
        String regex = "(quick)|(lazy)|(dog)";
        String text = "the quick brown fox jumps over the lazy dog";

        //
        // Obtain the required matcher
        //
        Pattern pattern = Pattern.compile(regex);
        Matcher matcher = pattern.matcher(text);

        int groupCount = matcher.groupCount();
        System.out.println("Number of group = " + groupCount);

        //
        // Find every match and print it
        //
        while (matcher.find()) {
            for (int i = 0; i <= groupCount; i++) {
                //
                // Group i substring
                //
                System.out.println("Group " + i + ": " + matcher.group(i));
            }
        }
    }
}

Below is the output...

Number of group = 3
Group 0: quick
Group 1: quick
Group 2: null
Group 3: null
Group 0: lazy
Group 1: null
Group 2: lazy
Group 3: null
Group 0: dog
Group 1: null
Group 2: null
Group 3: dog